Envariabelanalys: förenkla lösning på integral med ln och arctan

$$\begin{gathered} \left(\ln \right(2)-\frac{1}{2}-\frac{1}{2}\ln (5)-arc\tan (2\left)\right)-(0-1-\frac{1}{2}\ln (2)-\frac{\mathrm{\pi }}{4}) \\ ln\left(2\right)-\frac{1}{2}-\frac{1}{2}\ln \left(5\right)-arc\tan \left(2\right)+1+\frac{1}{2}ln\left(2\right)+\frac{\mathrm{\pi }}{4} ln\left(2\right)=\frac{2}{2}ln\left(2\right) , \frac{1}{2}ln\left(5\right)=\frac{ln\left(5\right)}{2} \\ \frac{3}{2}ln\left(2\right)+\frac{1}{2}-\frac{ln\left(5\right)}{2} -arc\tan \left(2\right)+\frac{\mathrm{\pi }}{4} \end{gathered}$$