komplexa tal

$x^{5} + 4 x^{3} + 3 x = 0 m i t t l ö s n i n g x (x^{4} + x^{2} + 3) = 0 x 1 = 0 x^{4} + x^{2} + 3 = 0 t = x^{2} t^{2} + t + 3 = 0 t = \frac{- 1}{2} \pm \sqrt{{(\frac{- 1}{2})}^{2} - 3} t = - 0.5 \pm \sqrt{2.75 \times i^{2}} j a g k o m m e r t i l l s v a r e n x 1 = \sqrt{0.5 + \sqrt{2.75} i} x 2 = \sqrt{0.5 + \sqrt{2.75} i} x 3 = 0 h a r j a g g j o r t k o r r e k t ?$

4:an från $4x^3$ har försvunnit.

$x^{5} + 4 x^{3} + 3 x = 0 x (x^{4} + 4 x^{2} + 3) = 0 x 1 = 0 x^{4} + 4 x^{2} + 3 = 0 t = x^{2} t^{2} + 4 t + 3 = 0 t = \frac{- 4}{2} \pm \sqrt{{(\frac{4}{2})}^{2} - 3} t = - 2 \pm 1 t 1 = - 1 t 2 = - 3 x^{2 = 3 i^{2}} x 1 = \sqrt{3} \times i x 2 = - \sqrt{3} \times i - x^{2} = 1 \times i^{2} x 3 = \sqrt{1 \times i^{2}} = i x 4 = - i x 5 = 0 s v a r : x 1 = 0 x 2 = - i x 3 = i x 4 = \sqrt{3} \times i x 5 = - \sqrt{3} \times i$

Jag gjort korrekt?

Ja.

Svara

Visa senaste svar