pH värdet igen

$$\begin{gathered} p{H}_1-p{H}_2=1 \\ -lg{\left[H^{+}\right]}_1-(-lg{\left[H^{+}\right]}_2)=1 \\ lg{\left[H^{+}\right]}_2-lg{\left[H^{+}\right]}_1=1 \\ lg\frac{{\left[H^{+}\right]}_2}{{\left[H^{+}\right]}_1}=1 \\ \frac{{\left[H^{+}\right]}_2}{{\left[H^{+}\right]}_1}={10}^1=10 \\ {\left[H^{+}\right]}_2=10{\left[H^{+}\right]}_1 \end{gathered}$$

Tack för det här